Find a number whose double is 39 greater than its half
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Answered by
1
Hi friend!!
Let the number be 'x'
Given
A number whose double is 39 greater than its half
→2x=(x/2)+39
2x-(x/2)=39
3x/2=39
x=78/3
x=26
So, the number is 26.
I hope this will help you ;)
Let the number be 'x'
Given
A number whose double is 39 greater than its half
→2x=(x/2)+39
2x-(x/2)=39
3x/2=39
x=78/3
x=26
So, the number is 26.
I hope this will help you ;)
Answered by
3
Let the number be 2x,
4x = 39 + x
4x - x = 39
3x = 39
x = 39/3 = 13
Required number is 2x = 2(13) = 26
I hope this will help you
(-:
4x = 39 + x
4x - x = 39
3x = 39
x = 39/3 = 13
Required number is 2x = 2(13) = 26
I hope this will help you
(-:
DhanyaDA:
Required number is 2x. so the required number will be 2(13)=26
please edit it bro
Dear, refresh your page
sry!
Tumhare khne ke phle..... Edit ho chuka tha.... lol
Its ok dear
oo
(-:
^_^
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