Math, asked by devansh43, 1 year ago

find a number whose double is 45 greater than its half

Answers

Answered by Anonymous
7
Please mark it as brainlist
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Answered by thamarai25
24
hello friend!!!!

here is ur answer!!!!

let the number be x
 2x+ 45 = x \div 2 \\ (2x + 45)2 = x \\ 4x +9 0 = x \\ 4x - x = 90 \\ 3x = 90 \\ x = 30
answer is 30
hope it helps u out
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