Question

find a number whose double is 45 greater than its half

Answer 1

Bonjour!

Let the number be x
2x = x/2 + 45
2x - x/2 = 45
(3x)/2 = 45
3x = 90
=> x = 90/3 = 30

Answer 2

Bonjour !!!❤❤❤
$let \: the \: number \: be \: x \\ \\ given \: \\ \\ 2x \: = \: \frac{1x}{2} \: + \: 45 \\ \\ 2x \: - \: \frac{1x}{2} \: = \: 45 \\ \\ \frac{4x \: - \: 1x}{2} \: = \: 45 \\ \\ \frac{3x}{2} \: = \: 45 \\ \\ x \: = \: 45 \: \times \: \frac{2}{3} \\ \\ x \: = \: 15 \: \times \: 2 \\ \\ x \: = \: 30$
Hope it helps....✌✌

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