Question

Find a pair of integers whose product is -15 and whose difference is 8​

Answer 1

Step-by-step explanation:

- 35 is your answer .

5×-3 =-15

5 -(-3)=8

Answer 2

let two integers be x and y

Acc. to question -

xy = -15 --- (1)

x-y = 8 -----(2)

In equation (2), x = 8+y

Put, x = 8+y in equation (1),

(8+y)y = -15

8y + y^2 = -15

8y + y^2 + 15 = 0

y^2 + 8y + 15 = 0

factorise by splitting the mid value,

y^2 + (5+3)y + 15 = 0

y^2 + 5x + 3y + 15 = 0

y(y + 5) + 3(y + 5) = 0

(y + 3)(y+5) = 0

Either, y+3 = 0 or y+5 = 0

when, y+3 = 0

y = -3

and when y+5 = 0

y = -5

Now, Put y = -3 in equation (2)

x - (-3) = 8

x + 3 = 8

x = 8 - 3 = 5

Again, Put y = -5 in equation (2)

x - (-5) = 8

x + 5 = 8

x = 8 - 5

x = 3

so, x = 3 and 5, and y = -3 and -5

so pair of numbers are --

(5,-3) or (3,-5)