Question

the HCF and LCM of two numbers are 12 and 72 respectively if the sum of the numbers is 60 then one of the number will be

Answer 1

Let the two numbers be x and y.

We know that.. product of two numbers = HCFx LCM.

Therefore XY= 12 x 72= 864….(1)

According to given condition, their sum is 60

Therefore x+y = 60……….(2)

We know that

(x-y)² =(x+y)² -4xy

Substitute values from 1 & 2

(X-y)² = 3600–4x864=144

X-Y =√144= 12…(3)

By solving 2 and 3

We get x=36 and y=24.

Answer 2

The method of quadratic equation