Question

Find a point on the curve y^2 = 8x for which the abscissa and ordinate change at the same rate

Answer 1

Hi I think when abscissa and ordinate changes at the same rate the implication is
$\frac{dy}{dx} = 1$
Now differentiate above equation and put dy/dx equal to one.
$2y \frac{dy}{dx} = 8 \\ 2y = 8 \\ y = 4$
Therefore x = 4^2/8 =2.
So the point is (2,4).
Hope this helps.