Question

find a point on the x-axis , which is equidistance from the point ( 7,6 ) and ( 3 ,4 ).
a). [15/2 ,2 ]
b). [5,15/2]
c). [15/2,0]
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Answer 1

Answer:

Hope it helps you friend.

Answer 2

Step-by-step explanation:

the point is (x, 0)

(x, 0)is equidistance from (7,6) (3,4)

(x-7) ^2+6^2=(x-3)^2+4^2

49-14x+36=9-6x+16

-14x+85=-6x+25

8x=60

x=15/2

point=(15/2,0)