find a point on the x axis which is equidistant from the point (7,6) and(-3,4)
Answers
Answered by
14
Point on x axis will be (x,0)
(x,0)=(7+{-3}/2 ,0)
= (4/3 ,0)
= (4/3 ,0)
yash510:
thnq
Plz mark me brainiest
why
I answered correctly
how
Answered by
3
7 to -3 distance is 10.
thnq
means
Similar questions