Question

Find a point on the y axis equidistant from (-5, 2) and (9, -2).

Answer 1

Answer:

(0,-7)

Step-by-step explanation:

Let the unkown point be (0,a). Consider the squares of distances of this point from the two given points:

$(-5-0)^2+(2-a)^2=(9-0)^2+(-2-a)^2\\25+4-4a+a^2=81+4+4a+a^2\\8a=-56\\a=-7$

Therefore, the required point is (0,-7)