Question

Find a point on the y-axis which is equidistant from the points A(6, 5) and B(−4, 3).

Answer 1

Let p(0,y) be qyuidistant from points.

=A(6,5) B(-4,3)

=PA=PB

=PA²=PB²

=(6-0)²+B(-4,3)

=PA=PB

=PA=PB²

=(6,5)+(5,y)²=(-4-0)²+(3-y)²

=36+25+y²=10y=16+9+y²-6y

=36+25-10y=25-6y

=36=4y

=y=36/4

= y=9

=it cordinate will be p(0,9)