Question

Find a point on the y-axis which is equidistant from the points A(6, 5)

and B(– 4, 3).​

Answer 1

Answer:

Step-by-step explanation:

let the point on y-axis be (0,y)

by using distance formula

[(6–0)[math]^2+(5-y)^2]^1/2=[(-4-0)^2+(3-y^2)]^1/2[/math]

Squarring both sides and solving…..

36[math]+25+y^2-10y=16+9+y^2-6y[/math]

61–10y=25–6y [y^2 cancel out]

36=4y

y=9

Point=(0,9