find measure of angle ACD
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in triangle bdc
angle dbc+angle dcb+angle bdc=180(a.s.p)
90+20+bdc=180
bdc=70
bdc+adc=180(linear pair)
70+adc=180
adc=110
in triangle adc
adc+dac+dca=180(a.s.p)
110+45+dca=180
dca=25
angle dbc+angle dcb+angle bdc=180(a.s.p)
90+20+bdc=180
bdc=70
bdc+adc=180(linear pair)
70+adc=180
adc=110
in triangle adc
adc+dac+dca=180(a.s.p)
110+45+dca=180
dca=25
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