Chemistry, asked by BrainlyHelper, 1 year ago

The net enthalpy change of a reaction is the amount of energy required to break all the bonds in reactant molecules minus amount of energy required to form all the bonds in the product molecules. What will be the enthalpy change for the following reaction: H_{2}(g) + Br_{2}(g) → 2HBr(g), Given that Bond energy of H_{2}, Br_{2} and HBr is 435 kJ mol^{-1}, 192 kJ mol^{-1} and 368 kJ mol^{-1} respectively.

Answers

Answered by GreenTree
2
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Answered by Harshikesh16726
1

Explanation:

ANSWER

Δ

r

H

=∑ bond enthalpies

reactants

=−∑ bond

enthalpies

products

Δ

r

H

=bond energy of H

2

+Bond crergy of Br

2

−2×Bond

energy of HBr

=435+192−(2×368)kJmol

−1

Δ

r

H

=−109KJmol

−1

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