Question

Find a point on x axis which is equadistant from (_3,_4)and(4,_3)

Answer 1

Answer:

Point ( -18,0)

Step-by-step explanation:

Distance formula= √( x2-x1)-(y2-y1)

Then

PA=PB

PA^2= PB^2

=>(a-3)^2+(0-4)^2=(a-4)^2+(0-3)^2

=>a^+17-6a=a^2+19-8a

=>-2a=36

=>a=-16

The point is (-18,0)

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