Question

find a point on x_axis which is equidistant from the points (7,6)and(-3,4)

Answer 1

x=x1+x2/2
x=7+(-3)/2
x=7-3/2
x=4/2
x=2

Answer 2

Let P be any point on the axis which is equidistant from Q (7, 6) and R (3, 4).

We have distnce between two points and is

PQ = √(x-7)² + (0-6)²

= √ (x² -14x +85)

And PR = √ (x- 3)²+ (0-4)²

= √

According to question, PQ = PR

=

Squaring both sides, =

Therefore, the required point is