Question

Find a point on y-axis equidistant from (-5, 2) and (9,2)

Answer 1

Answer:

Point on y axis has x-coordinates as O

∴ Let that point be P(O,y)

Let

A≡(−5,2) & B≡(9,−2)

A.T.Q

PA=PB

By distance formula

√(0−(−5)2+(y−2)2)

=√(0−9)2+(y−(−2)2)

As PA=PB

∴PA2=PB2

∴25+(y−2)2

=81+(y+2)2

∴25+y2−4y+4

=81+y2+4y+4−8y=56

y=−7

According to question

(0,y)≡(0,−m)

(0,−7)≡(0,−m)

∴m=7

Step-by-step explanation:

I hope this helps