Question

Find a point on y-axis which is equidistant from the points A (6,5) and B ( -4,3).

Answer 1

Answer:

let the point on y axis is P(0,y)

a/q PA=PB, So

$(0 - 6) {}^{2} + (y - 5) { }^{2} = (0 + 4) {}^{2} + (y - 3) {}^{2}$

Step-by-step explanation:

$36 + {y}^{2} - 10y + 25 = 16 + {y}^{2} - 6y + 9$

$4y = 36$

$y = 9$

so point is (0,9)