Find a polynomial whose zeroes are square of the zeroes of the polynomial. 3x square +6x- 9
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Sol: Given polynomial 3x2 + 6x - 9 = 0 ⇒ 3x2 + 9x -3x - 9 = 0 3x( x + 3) -3( x + 3) = 0 3x - 3 = 0 , x + 3 = 0 x = 1 , x = - 3. Given that zeroes are square of the zeroes of the polynomial so that x = 1, 9 Sum of the roots α + β = 10. Product of the roots αβ = 9 According to the question x2 -(α + β)x + αβ = 0 ∴ the polynomial is x2 -10x + 9 = 0.
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x 1,9 Kaise Aaya
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