Find a positive number which when increased by 17 is equal to 21 times the reciprocal of the number
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Let the positive number be x.
Given that A number when increased by 17 is equal to 60 times the reciprocal of the number.
= x + 17 = (60/x).
= x(x + 17) = 60
= x^2 + 17x = 60
= x^2 + 17x - 60 = 0
= x^2 - 3x + 20x - 60 = 0
= x(x - 3) + 20(x - 3) = 0
= (x - 3)(x + 20) = 0
= x = 3, -20[Neglect negative values]
= x = 3.
Therefore, the positive number is 3.
Hope this helps!
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