Question

The sum of the 4th and 8th terms of an Ap is 24 and the sum of the 6th and 10th term is 44 find the first three terms of the Ap

Answer 1

Step-by-step explanation:

given..... t4 + t8 = 24 and t6 + t10 = 44

t4 = a + 3d

t8 = a + 7d

t4 + t8 = a + 3d + a + 7d

24 = 2a + 10d

24 = 2 ( a + 5d )

a + 5d = 12... ( equation 1 )

t6 = a + 5d

t10 = a + 9d

t6 + t10 = a + 5d + a + 9d

44 = 2a + 14d

44 = 2 ( a + 7d )

a + 7d = 22.... ( equation 2 )

equation 1 - equation 2

a + 5d - ( a + 7d ) = 12 - 22

a + 5d - a - 7d = - 10

-2d = -10

2d = 10

d = 5....

a + 5d = 12

a + 5 ( 5 ) = 12

a = 12 - 25

a = - 13.....

first 3 terms of AP = a , a+d , a + 2d

= -13 , -13 + 5 , -13 + 10

first 3 terms of AP = -13 , - 8 , - 3.

hope it helps.....