Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.
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let tne number is x
so,
x+17=60/x
or x^2 +17x -60 = 0
or x^2 +20x-3x-60=0
or x(x+20)-3(x+20)=0
or (x+20)(x-3)=0
either x+20=0
x=-20
or x-3=0
x=3
x is not negetive
so x is 3
ans: the number is 3
so,
x+17=60/x
or x^2 +17x -60 = 0
or x^2 +20x-3x-60=0
or x(x+20)-3(x+20)=0
or (x+20)(x-3)=0
either x+20=0
x=-20
or x-3=0
x=3
x is not negetive
so x is 3
ans: the number is 3
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