Question

Find a positive root of x3-4x-9=0 using bisection method up-to 3 decimal values

Answer 1

Answer:

Step-by-step explanation:

Hence the required root is x_4=2.6875.

Step-by-step explanation:

Given:

Let  

Then f(1) == -12

f(2)= = 8-8-9= -9

f(3)==27-12-9= 6

Here f(2) is -ve and f(3) is positive. Therefore root lies in (2,3)

Hence the first approximation to the root is  

               = -3.375

Root lies between 2.5 and 3

Root lies between 2.5 and 2.75.

Root lies between 2.625 and 2.75.

Hence the required root is .