Math, asked by wecwc5390, 11 months ago

Find a positive value of k for which x square + kx + 64 is equal to zero and x square - 8 x + k is equal to zero will have real roots

Answers

Answered by rishika79
4

Answer:

Step-by-step explanation:

Let D₁ and D₂ be the discriminant of the given equations and these will have equal roots only if D₁, D₂ ≥ 0

Or, if D₁ = (k² -4 × 64) ≥ 0  and D₂ = (64 - 4k) ≥ 0

Or,  if k² ≥ 256  and  4k ≤ 64

Or, if k ≥ 16  and  k ≤ 16

Or, k = 16

Hence the positive value of k is 16

Hope it helps you....

Answered by Aashnamanocha
2

Answer:16

Step-by-step explanation:

See the attachment

Attachments:
Similar questions