Question

Find a Pythagorean triplet for which
1). one member is 4
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Answer 1

answer:let 2m= 4m

m=2^2

m=2m^2+1 = 2^2 +1 =4+1 =5m

m^2-1= 2^2-1 = 4-1=3m

so the triplets are 4^2 , 3^2 and 5^2

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Answer 2

Step-by-step explanation:

Pythagorean triplet=2m,(m²+1)and (m²-1)

let 2m=4

so, by putting the value in the formula

2m=4

m=4/2

m=2

now

(m²+1)=2x2+1

=4+1

=5

and,

(m²-1)=2x2-1

=4-1

=3

proof,

3²+4²=5²

9+16=25

25=25

LHS=RHS

hence proved..

so the Pythagorean triplet is 3,4 and 5.

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