Question

find a pythagorean triplet for which greatest member is 101

Answer 1

Hi friend!!

The Pythagorean triplet which contains 101 as it's member is (20,99,101)

→20²+99²=101²

400+9801=10201

10201=10201

I hope this will help you ;)

Answer 2

Hey dood ur answer is here ---

Pythgorean triplet = 2m , m² - 1 , m² + 1

In pythagorean triplet greatest member is m² + 1
m² + 1 = 101
m² = 101 - 1
m = √100
m = 10
so pythgorean triplet = 2m , m² - 1 , m² + 1
Placing m = 10
= 2 ( 10 ) , ( 10 )² - 1 , 101
= 20 , 100 - 1 , 101
= 20 , 99 , 101

Hope it helps