Question

find a pythagorean triplet in which one member is 6.​

Answer 1

Answer:

Step-by-step explanation:

THE REQUIRED PYTHAGORIAN TRIPLET IS :6,8,10.

HOPE THIS HELPS.

Answer 2

Answer:

Pythagorean Triplet is 6,8, and 10

Step-by-step explanation:

$take \: {m}^{2} = 6 \\ then \: {m}^{2} = 6 + 1 = 7. \ \: \\ here \: the \: value \: of \: (m) \: \\ will \: not \: be \: an \: integer \\ so \: we \: try \: again. \\ take \: {m}^{2} = 6.again \: {m}^{2} = 5 \\ which \: will \: not \: an \: integer \\ \\ hence \: let \: us \: take \: 2m = 6 \\ then \: \\ {m}^{2} - 1 = 9 - 1 = 8 \: and \: \\ {m}^{2} + 1 = 9 + 1 = 10$

Therefore, the required triplet is 6,8,10