find a pythagorean triplet whose largest member is 37
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37, 35 , 12
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Step-by-step explanation:
As we know 2m, m 2 + 1 and m2 - 1 form a Pythagorean triplet for any number, m > 1.
Let's assume
M^2+1=37
Then, M^2=36
And M=6
Now put the value of M
2M = 12
M^2+1=37
M^2-1=35
The triplets are 37, 35 and 12
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