find a Pythagorean triplet whose one member is 15
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Answer:
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Step-by-step explanation:
As a Phytagorean Triplets is taken by 2m, m^{2}m2 - 1 and m^{2}m2 + 1
Since 2n is the smallest, 2n = 15
n = 15 ÷ 2
n = 7.5
Second member = 7.5^{2}7.52 - 1
= 55.25
Third member = 7.5^{2}7.52 + 1
= 57.25
Hence the 3 members are 15, 55.25 and 57.25
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