Question

find a pythagorean triplet whose the smallest member is 10

Answer 1

let Pythagoras triplets be 2m,m^2+1,m^2-1.now 2m=10,m=5,therefore m^2+1=5^2+1=26,and m^2-1=5^2-1=24.hence triplets will be 10,24,26

Answer 2

Dear Student,

◆ Answer -

10, 24 and 26

● Explanation -

Pythagorean triplet is given by 2m, m^2-1 and m^+1.

As 10 is smallest member of required triplet,

2m = 10

m = 5

Then other two numbers are -

m^2 - 1 = 5^2 - 1 = 25 - 1 = 24

m^2 + 1 = 5^2 + 1 = 25 + 1 = 26

Hence, required Pythagorean triplet is 10, 24 and 26.

Thanks dear. Hope this helps you...