find a pythagoren triplet whose greatest member is 29
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phthagorean triplet is a set of positive integers. a,b,c which is "a square,+b square = c square"when we make a triangle with sides a,b,c then it is a right angled triangle.c is hypotheneus is the longest sidewhere,a and b are other two sides
15 square -14 square = 225-196= 29 (odd number)
15 square -14 square = 225-196= 29 (odd number)
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greatest triplet = m^2+1
m^2+1=29
m^2=28
m=√28
2m=2×√28=2√14
m^2-1=2√7^2-1=27
m^2+1=2√7^2+1=29
m^2+1=29
m^2=28
m=√28
2m=2×√28=2√14
m^2-1=2√7^2-1=27
m^2+1=2√7^2+1=29
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