Find a quadatic polynomial whose zeros are 2 and -5
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Answer:
b=3
c=-10
a=1
Step-by-step explanation:
α+β=-b/a
2+(-5)=-b/a
-3=-b/a
αβ=c/a
2(-5)=c/2
-10=c/a
=x²-(α+β)x+(αβ)
=x²-(-3)x-10
=x²+3x-10
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