Question

find a quadratic equation polynomial if the zeros of it are -3,and 2​

Answer 1

Answer:

${x}^{2} + x - 6$

Step-by-step explanation:

sum of the zeroes: 2-3= -1

product of the zeroes: 2×-3 = -6

Equation :

${x}^{2} - ( - 1)x + ( - 6) \\ {x}^{2} + x - 6$

Answer 2

Answer:

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Step-by-step explanation:

x^2-(α+β)x+αβ

x^2-(2-3)x+(2×-3)

x^2+x-6