Question

find a quadratic equation with 0 as 3+√5 and 3-√5​

Answer 1

Step-by-step explanation:

i think your question is incorrect

Answer 2

Step-by-step explanation:

${x}^{2} - 6x + 4 = 0$

Std form =x^2-(sum of roots) x+product of roots=0

Sum of roots=6

Pdt of roots=9-5=4

Quadratic eqn( x}^{2} - 6x + 4 = 0