find a quadratic equations by factorisation method,abx2+(b2-ac)x-bc=0
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Hi ..dear....
here is your answer!!
..
no need to split middle term..it's already done!!!
.
abx2 +(b2-ac)x-bc = 0
⇒ abx2 + b2x – acx – bc = 0
⇒ bx (ax + b) – c(ax + b) = 0
⇒ (ax + b)(bx – c) = 0
......
...
x=-b/a
or
x=ç/b....
hope this helps you!!!
Regards Brainly Star Community
#shubhendu
here is your answer!!
..
no need to split middle term..it's already done!!!
.
abx2 +(b2-ac)x-bc = 0
⇒ abx2 + b2x – acx – bc = 0
⇒ bx (ax + b) – c(ax + b) = 0
⇒ (ax + b)(bx – c) = 0
......
...
x=-b/a
or
x=ç/b....
hope this helps you!!!
Regards Brainly Star Community
#shubhendu
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