find a quadratic polynomial each with the given numbers as sum and product of its zeros respectively
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Solution :-
Let α, β be the zeroes of the polynomial
Given :-
- Sum of zeroes = α + β = √2
- Product of zeroes = αβ = - 3/2
We know that
Quadratic polynomial = k{ x² - x(α + β) + αβ }
[ Where k ≠ 0 and α,β are the zeroes of the polynomial ]
= k{ x² - x(√2) + (-3/2) }
= k(x² - √2 x - 3/2)
= k{ (2x² - 2√2 x - 3)/2 }
When k = 2
= 2{ (2x² - 2√2 x - 3)/2 }
= 2x² - 2√2 x - 3
Therefore the polynomial is 2x² - 2√2 - 3
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