Question

Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively. From that, find the zeroes of the polynomial:
2÷3,-8÷9​

Answer 1

ANSWER:

given that,

• sum of zeroes = (2/3)

product of zeroes = (-8/9)

SO,

→ x² - (sum of zeroes)x+ product of

zeroes = 0

→ x² - (2/3)x + (-8/9) = 0

→ x² - (2x/3) - (8/9) = 0

→ (9x² - 6x - 8) /9 = 0

9x² - 6x - 8 = 0 (Ans.)

Step-by-step explanation:

above