Math, asked by abhinob29, 1 year ago

find a quadratic polynomial each with the given numbers as the sum and product of its zeros respectively
-1/4,1/4.​

Answers

Answered by waqarsd
9

given \\  \alpha  +\beta=  \frac{ - 1}{4} \\  \alpha\beta  =  \frac{1}{4}  \\ the \: q \: e \: is \\  {x}^{2}  - ( \alpha  +  \beta )x  +  \alpha  \beta  = 0 \\  {x}^{2}  + (\frac {-1}{4})x -  \frac{1}{4}  = 0 \\ 4 {x}^{2}+x  +1 = 0

hope it helps

Answered by Anonymous
2
7Hey Ma8,
***

α+β = -b/a = -(+1)/4

α×β = C/a = 1/4

quadratic polynomial is in The form of ax^2 + bx + c

4x^2 + 1x + 1

hence required number is 4x^2 + 1x + 1


*****

this is right ans
you also see in ncert book 10th exercise 2.2 question 2 part 5

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