Find a quadratic polynomial given whose zeroes are -6 and - 2/3
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Let the zeroes of the quadratic polynomial be α = 3 , β = – 3 Then, α + β = 3 + ( – 3) = 0 αβ = 3 × ( – 3) = – 9 Sum of zeroes = α + β = 0 Product of zeroes = αβ = – 9
Then, the quadratic polynomial = x2 – (sum of zeroes)x + product of zeroes = x2 – (0)x + ( – 9) = x2 – 9.
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