Find a quadratic polynomial PX with three and minus 2 by 5 as sum and product of this zero respectively
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assume a=3 as one root and b=-2/5 as the other.
Sum of roots=3+(-2/5)=13/5
Product of roots=3*-2/5= -6/5
Therefore, we form the equation using-
x^2 - (sum of roots)*x + (product of roots) = 0
x^2 - (13/5)*x + (-6/5) = 0
x^2 - 13x/5 - 6/5 = 0
if we take LCM and simplify, we finally get-
5x^2– 13x - 6 = 0.
Thank you.
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