find a quadratic polynomial sum of whose zero is root 3 and product is 10
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Answer:
let α & β be two zeroes of p(x)
given,
α+β = √3
αβ = 10
p(x) = x²-(α+β)x+αβ
= x²-√3x+10
Answered by
0
Step-by-step explanation:
α+β=√3
αβ = 10
so the polynomial is
x^2-√3x +10
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