Find a quadratic polynomial the sum and
product of whose Zeroes are 1 and -12
respectively. Hence find the zeroes.
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Answer:
k{ x² - x - 12} is the required polynomial.
Therefore, by factorizing the polynomial, we get
x² - x - 12
= x² - 4x + 3x - 12
= x(x - 4) + 3(x - 4)
= (x - 4)(x + 3)
Now,
α ⇒ x - 4 = 0
⇒ x = 4
β ⇒ x + 3 = 0
⇒ x = - 3
Hence, α and β or the two zeroes f the polynomial are 4 and (-3) respectively.
Step-by-step explanation:
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