Question

find a quadratic polynomial , the sum and product of whose zeroes are 6 and 8 , respectively​

Answer 1

hope it will help you

the polynomial is x^2 - 6x + 8

Answer 2

Answer:

$x^{2}$ - 6x + 8

Step-by-step explanation:

Given:- Sum of zeroes = 6, Product of zeroes = 8

To Find:- Quadratic polynomial

Solution:-

Sum of zeroes = 6, Product of zeroes = 8

As we know,
Quadratic polynomial = $x^{2}$ - (Sum of zeroes)x + (Product of zeroes)

∴ Quadratic polynomial = $x^{2}$ - 6x + 8

⇒  $x^{2}$ - 6x + 8 = 0

⇒ (x-2)(x-4) = 0

∴ x =2, 4

Hence, the roots are 2 and 4.

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