Math, asked by sehajpreetsingh073, 9 months ago

Find a quadratic polynomial, the sum and products of whoose zerores are 1/4 & -1 respectively

Answers

Answered by Anonymous
6

Answer:

4x^2 - x - 4

Step-by-step explanation:

Polynomial = kx^2 - (sum of zeroes)x + product of zeroes

= kx^2 - x/4 - 1

= 4x^2 - x - 4

Answered by ShírIey
218

\huge{\underline{\underline{\pink{\mathcal{Solution}}}}}:-

We know that,

Sum of Zereos = \bold{ \alpha \; + \; \beta}

Product of zereos = \bold{\alpha \; \beta}

If \alpha and \beta are zeroes of any quadratic polynomial then the quadratic equation can be written as :-

 \boxed {x^2 \;- \; \left( \alpha \; + \; \beta \right)\;x\; +\; \alpha\; \beta}

Sum of zereos =  \frac{1}{4}

Product of zereos = - 1

\implies x^2 - \frac{1}{4} \; x \; +\; -1 \; = 0

\implies\bold{ 4x^2 \; - \; x \; - \;4}

Thus, 4x² - x - 4 is the quadratic polynomial.

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Anonymous: Awesome
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