Question

if a^2+ b^2 + c^2 = 74 and ab + bc + ac = 61 find a+b+c

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Answer 1

Answer:

we have to use the formula (a+b+c)^2

= a^2+b^2+c^2+2ab+2bc+2ca

Answer 2

Answer:

(a+b+c)^2= a^2+b^2+c^2+2(ab+bc+ca)

(a+b+c)^2=74+2 x 61

=74+122

=196

(a+b+c)= root of 196

=14

Hope it helps :D

Mark this the brainliest answer.