Question

find a quadratic polynomial, the sum of product of whoes zeroes are 3/4 and -2 respectively

Answer 1

Answer:

$\alpha + \beta = 3 \div 4 \\ \alpha \beta = - 2 \\ \\ polynomial \: is \\ \\ {x}^{2} - 3 \div 4 - 2 \\ or \\ \\ 4 {x}^{2} - 3 - 8$

Answer 2

Answer:

Sum of the zero =-3/4

Product=-2

A+B=-3/4

AB=-2

By the general formula:

x^2-(A+B)x +AB=0

NOW, substitute

x^2-(-3/4)x+(-2)=0

4x^2-3x-8=0