Find a quadratic polynomial whose one zero is 5 and product of zeroes is 30.
Answers
Answered by
150
Hiiii friend,
Let Alpha and beta are the zeros of the Quadratic polynomial.
Alpha = 5
Product of zero = 30
(Alpha × Beta) = 30
5 × Beta = 30
Beta = 30/5 = 6
Alpha = 5 and Beta = 6
Therefore,
Sum of zeros = (Alpha + Beta) = (5+6) = 11
And,
Product of zeros = (Alpha × Beta) = (5×6) = 30
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X+Alpha × Beta
=> X²-(11)X +30
=> X²-11X+30
HOPE IT WILL HELP YOU........ :-)
Let Alpha and beta are the zeros of the Quadratic polynomial.
Alpha = 5
Product of zero = 30
(Alpha × Beta) = 30
5 × Beta = 30
Beta = 30/5 = 6
Alpha = 5 and Beta = 6
Therefore,
Sum of zeros = (Alpha + Beta) = (5+6) = 11
And,
Product of zeros = (Alpha × Beta) = (5×6) = 30
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X+Alpha × Beta
=> X²-(11)X +30
=> X²-11X+30
HOPE IT WILL HELP YOU........ :-)
Answered by
33
5 × Beta = 30
Beta = 30/5 = 6
Alpha = 5 and Beta = 6
Therefore,
Sum of zeros = (Alpha + Beta) = (5+6) = 11
And,
Product of zeros = (Alpha × Beta) = (5×6) = 30
Therefore,
Required Quadratic polynomial = X²-(Alpha + Beta)X+Alpha × Beta
=> X²-(11)X +30
=> X²-11X+30
HOPE IT WILL HELP YOU
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