Find a quadratic polynomial whose one zero is -8 and sum of zeroes is 0.
Class 10th
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Hey! Here is ur answer...
Let two zeros be a nd b
Now, a = - 8
(a + b) = 0
(-8 + b) = 0
b = 8
ab = - 64
So, P(x) = x^2 - (a + b)x + ab
= x^2 - (0)x - 64
= x^2 - 64
Hope it will help u... Plz mark it as brainliest...
Let two zeros be a nd b
Now, a = - 8
(a + b) = 0
(-8 + b) = 0
b = 8
ab = - 64
So, P(x) = x^2 - (a + b)x + ab
= x^2 - (0)x - 64
= x^2 - 64
Hope it will help u... Plz mark it as brainliest...
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