Question

find a quadratic polynomial whose pne zero is 7 and sum of zeroes is -18​

Answer 1

Answer:

x2+18x-77

Step-by-step explanation:

sum

-18 =-7+beta

beta =-7+18

beta =11

product

-7×11

-77

so quadratic equation is

x2 -(sum)x +(product)

x2-(-18)x+(-77)

x2 +18x-77

Answer 2

Answer

The required quadratic polynomial is :

x² + 18x + 7

$\bf\large\underline{Given}$

• Sum of the zeroes is -18
• Product of the zeroes is 7

$\bf\large\underline{To \: Find}$

• The quadratic polynomial

$\bf\large\underline{Solution}$

We know that , if sum and product of a quadratic polynomial is given then it is given by ,

$\sf \longrightarrow {x}^{2} - (sum \: of \: zeroes)x + product \\ \\ \sf \longrightarrow {x}^{2} - ( - 18)x + 7 \\ \\ \sf \longrightarrow {x}^{2} + 18x + 7$