Question

find a quadratic polynomial whose roots are (a+b) and (a-b)and a, b are roots of 4a^2+8a​

Answer 1

Answer:

X^2-4

Step-by-step explanation:

4a^2+8a=0

4a(a+2)=0

∴Roots of equation is a=0 and b=-2

(a+b)=0-2=-2

(a-b)=0-(-2)=2

sum of roots=2-2=0

product of roots=2 x (-2)=(-4)

Equation=X^2+(sum of roots)X+(product of roots)

              =X^2+(0)X+(-4)

              =X^2-4

Answer 2

Hope it helps

First factorise the given polynomial and find it's zeroes .

Then obtain the new zeroes

Put them in the formula

And you get your answer