Question

Find a quadratic polynomial whose sum and product of the zeroes are 8/3 and 7.

Answer 1

$\textbf{Hey!}$

Sum of zeroes

$\alpha + \beta = \frac{8}{3} \\ \\product \: of \: zeroes \\ \\ \alpha \beta = 7$

Required polynomial

$= x {}^{2} - ( \alpha + \beta )x + \alpha \beta \\ \\ = x {}^{2} - \frac{8}{3} x + 7 \\ \\ = 3x {}^{2} - 8x + 21 > > answer$

$\boxed{3x{} ^{2} - 8x + 21}$

Answer 2

Hi Mate !!

Here is your answer :

Question : Find a quadratic polynomial whose sum and product of the zeroes are 8/3 and 7.

Solution :

Sum of zeroes ( S ) = 8/3.

And,

Product or zeroes ( P ) = 7

Therefore,

Required quadratic polynomial = X² - ( Sum of zeroes)X + Product of zeroes.

=> X² - ( S )X + P

=> X² - ( 8/3) X + 7

=> X² - 8x/3 + 7

=> 3x² - 8x + 21 [ Answer ]

Hence,

therefore the Quadratic polynomial equal to 3x² - 8x + 21.

Hope it helps you ♥

By Rishi 403.

BeBrainly..